[lxml-dev] Next question (Was: Beginner question)

[Frederik Elwert]

Andreas Tille schrieb:
> On Tue, 16 Oct 2007, Frederik Elwert wrote:
> 
>>            elif lname(elem) == 'vaccination':
>>                print 'vaccination status response:',\
>>             elem.find('status').get('response')
>>            elif lname(elem) == 'therapy':
>>                print 'therapy status response:',\
>>             elem.find('status').get('response')
>>
>> I think this should help.
> 
> It sounds promissing but does not help:
> 
>             elif event == 'end'  and lname(elem) == 'vaccination':
>                 print 'vaccination:', etree.tostring(elem, 
> pretty_print=True)
>                 stat = elem.find('status')
>                 if stat != None:
>                     print 'vaccination status response:', 
> elem.find('status').get('response')
>                 else:
>                     print 'status not found'
> 
> 
> vaccination: <vaccination>
>            <status response="n"/>
>          </vaccination>
> 
> status not found
> 
> 
> Did I missed something?

Probably a namespace issue, I forgot that. In a namespace aware 
application, you would use something like
elem.find('{http://my-namespace/}status')

Now since you want to avoid namespaces, it will get a bit more tricky. 
Maybe something like this helps:

             elif event == 'end'  and lname(elem) == 'vaccination':
                 print 'vaccination:', etree.tostring(elem,
pretty_print=True)
                 try:
                     print 'vaccination status response:',
elem.xpath('./*[local-name() = "status"]')[0].get('response')
                 except IndexError:
                     print 'status not found'


Or you simply iter the children and test for lname():

             elif event == 'end'  and lname(elem) == 'vaccination':
                 print 'vaccination:', etree.tostring(elem,
pretty_print=True)
                 for child in elem:
                     if lname(child) == 'status':
                         print 'vaccination status response:',
child.get('response')


I cc'd this to the list, what I forgot to do before, since there are the 
experts that might have better ideas.

Frederik