[Cython] long long and VC6

[Michael Abshoff]

Kirill Simonov wrote:
> Hi Robert,

Hi,

>>> I'm using Cython 0.10.3 to build an extension module and the  
>>> generated C
>>> file does not compile under VC6, which I use to create a Windows  
>>> binary
>>> package for Python 2.3.  The culprit is the following expression:
>>>
>>> PyObject *j = (likely(i >= 0) || !is_unsigned) ? PyInt_FromLong(i) :
>>> PyLong_FromUnsignedLongLong((sizeof(unsigned long long) >
>>> sizeof(Py_ssize_t) ? (1ULL << (sizeof(Py_ssize_t)*8)) : 0) + i);
>>>
>>> in the function __Pyx_GetItemInt.  It looks like VC6 does not know  
>>> about
>>> "long long".  I suppose Cython should respect HAVE_LONG_LONG and use
>>> PY_LONG_LONG macro instead of "long long".
>> Hmm... I don't have any experience with VC6, but it looks like a bug  
>> to me. Could you file a bug report on trac? Also, do you know if  
>> PY_LONG_LONG guaranteed to be 64+ bits?
> 
> I can't file a bug report, got Forbidden here:
> 
> http://trac.cython.org/cython_trac/newticket
> 
> I don't know about PY_LONG_LONG on 64+, but long long is C99, so I 
> suppose it's a reasonably safe assumption.

I am not sure what Python 2.3 does, but the standard workaround for VC 6 
is to define long long as __int64. But if PY_LONG_LONG is supported I 
would obviously recommend to use that.

> Thanks,
> Kirill.

Cheers,

Michael

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